30. At 298 K, a 1 litre solution containing 10mmol of Cr2O72− and 100mmol of Cr3+ shows a pH of 3.0. Given: Cr2O72− → Cr3+; E∘ = 1.330 V and “2.303RT” /”F” = 0.059 V The potential for the half cell reaction is × 10−3 V. The value of is

NCERT Solutions The candidates who are studying under CBSE board and in search for NCERT Solutions can refer this website to your friends and relatives. In this Website, we have NCERT Solutions for Class 12 for the Chemistry subject updated. The NCERT Solutions for class12 has been written in order to help the students in all the level of grades. Has given detailed solutions for all the questions keeping the marking scheme for each question. This in turn, helps you ace the exam with High grades.

These NCERT Solutions will not only help students to score good marks in their class tests, board exams but also helps to clear the toughest competitive exams like NEET, JEE Main, JEE Advanced, AIIMS etc., Read on to find out everything about NCERT Solutions for class 12 here.

The NCERT solutions provided here will enhance the concepts of the students, as well as suggest alternative methods to solve particular problems. The target is to direct individuals towards problem solving strategies, rather than solving problems in one prescribed format.

Chemistry is the language of Science. We have made sure that our solutions reflect the same. We aim to aid the students with answering the questions correctly, using logical approach and methodology.

Section =B #jee MAIN #2023 24-January-2023

30. At 298 K, a 1 litre solution containing 10mmol of Cr2O72− and 100mmol of Cr3+ shows a pH of 3.0. Given: Cr2O72− → Cr3+; E∘ = 1.330 V and "2.303RT" /"F" = 0.059 V The potential for the half cell reaction is × 10−3 V. The value of is

Leave a Comment

Your email address will not be published. Required fields are marked *